GeminiHeat wrote:
\(\sqrt{\frac{28a^{6}b^4}{36a^4{b}^6}}=\)
(A) \(\frac{a}{b}\) \(\sqrt{\frac{a}{2b}}\)
(B) \(\frac{a}{2b}\) \(\sqrt{\frac{a}{b}}\)
(C) \(\frac{|A|}{3|B|}\) \(\sqrt{7}\)
(D) \(\frac{a^2}{3b^2}\) \(\sqrt{2}\)
(E) \(\frac{2a}{3b}\)
\(\sqrt{\frac{28a^{6}b^4}{36a^4{b}^6}}\)
\(\sqrt{\frac{(2)(2)(7)(a^2)(a^2)(a^2)(b^2)(b^2)}{(6)(6)(a^2)(a^2)(b^2)(b^2)(b^2)}}\)
\(\frac{2(a^3)(b^2)\sqrt{7}}{6(a^2)(b^3)}\)
\(\frac{a\sqrt{7}}{3b}\)
Hence, option C