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If we divide 5000
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09 Apr 2021, 05:02
09 Apr 2021, 05:02
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If we divide 5000 into \((k^2-16)\) equal parts where \((\frac{k+4}{25})\) % of each part is equal to 1 what is k ?
Show: :: OA
6
If we divide 5000
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09 Apr 2021, 08:51
09 Apr 2021, 08:51
\(\frac{5000 }{ (k^2 - 16)} = \frac{5000 }{ (k+4) (k-4)}\)
This is a single piece of 5000 after division.
\(\frac{k+4}{25} percent * \frac{5000 }{ (k+4) (k-4)} = 1\)
\(\frac{k+4}{25} * \frac{1}{100} * \frac{5000 }{ (k+4) (k-4)} = 1\)
Cancelling out k+4, we can solve for k, getting k=6.
Hence, 6 is my answer.
This is a single piece of 5000 after division.
\(\frac{k+4}{25} percent * \frac{5000 }{ (k+4) (k-4)} = 1\)
\(\frac{k+4}{25} * \frac{1}{100} * \frac{5000 }{ (k+4) (k-4)} = 1\)
Cancelling out k+4, we can solve for k, getting k=6.
Hence, 6 is my answer.
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Re: If we divide 5000
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09 Apr 2021, 08:55
09 Apr 2021, 08:55
1
Carcass wrote:
If we divide 5000 into \((k^2-16)\) equal parts where \((\frac{k+4}{25})\) % of each part is equal to 1 what is k ?
Show: :: OA
6
\(5000\) into \((k^2-16)\) means \(\frac{5000}{(k^2-16)}\)
So, \((\frac{5000}{(k^2-16)})(\frac{k + 4}{2500}) = 1\)
\(\frac{(k + 4)}{(k + 4)(k - 4)} = \frac{1}{2}\)
\(k - 4 = 2\)
\(k = 6\)
