Carcass wrote:
A certain candy store sells jellybeans in the following six flavors only: banana, chocolate, grape, lemon, peach and strawberry. The jellybeans are sorted into boxes containing exactly 2, 3 or 4 different flavors, with each possible assortment of flavors appearing in exactly one box. What is the probability that any given box contains grape jellybeans?
A. 16
B. 13
C. 25
D. 12
E. 34
Here,
In this type we find the probability of no grape then 1 - probability of no grape will give the answer
To start with let us take the first option of the box containing 2 flavors:Therefore the probability of box containing 2 flavors =
13(Since there are 3 box containing 2 flavors, 3 flavors or 4 flavors)
Now probability of no grape in that box =
56∗45=23.
Therefore the probability of having 2 flavors and no grape =
13∗23=29.
the probability of box containing 3 flavors = 13(Since there are 3 box containing 2 flavors, 3 flavors or 4 flavors)Probability of no grape in the 3 flavor box =
56∗45∗34=12.
Therefore the probability of having 2 flavors and no grape =
13∗12=16.
the probability of box containing 4 flavors = 13(Since there are 3 box containing 2 flavors, 3 flavors or 4 flavors)Probability of no grape in the 4 flavor box =
56∗45∗34∗23=13.
Therefore the probability of having 4 flavors and no grape =
13∗13=19.
Therefore probability of no grape in 2, 3 or 4 flavor box =
29+16+19=12.
Therefore the probability of having grape in any given box =
1−12=12.