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Dataset A consists of 5 numbers, which have an average (arit
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30 Aug 2018, 07:31
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Dataset A consists of 5 numbers, which have an average (arithmetic mean) value of 43. Dataset B consists of 5 numbers.
Quantity A
Quantity B
The value of x if the average of x and the 5 numbers in dataset A is 46.
The average of dataset B if the average of the 10 numbers in datasets A and B combined is 52.
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
Re: Dataset A consists of 5 numbers, which have an average (arit
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26 Sep 2018, 22:27
4
While @Saifee's answer is correct, it may take some time to do some multiplications. In the GRE you've got to be quick and look for short cuts.
First let's solve A :
x is some value added to the Dataset A which makes it's average increase from 43 to 46. There are 5 elements in Dataset A , so to increase avg from 43 to 46, it's as good as adding 3 to each of the 5 elements. After this, the average is 46 in Dataset A and we also have to add x (sixth element) while making sure that avg remains 46. So what value of x will keep the avg 46 ? x = 46 will do that. Now, the new element added is 3*5 + 46 = 61.
Solve B :
Since we are finding avg of 2 lists with same number of elements, we can simply average the averages. That is,
(43 + X)/2 = 52
X = 61
Hence answer is C. This seems long but once you get the hang of it, you can avoid long calculations and can do all this mentally.
Re: Dataset A consists of 5 numbers, which have an average (arit
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28 Dec 2020, 06:22
1
sandy wrote:
Dataset A consists of 5 numbers, which have an average (arithmetic mean) value of 43. Dataset B consists of 5 numbers.
Quantity A
Quantity B
The value of x if the average of x and the 5 numbers in dataset A is 46.
The average of dataset B if the average of the 10 numbers in datasets A and B combined is 52.
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
Dataset A consists of 5 numbers, which have an average (arithmetic mean) value of 43. (sum of all 5 numbers in set A)/5 = 43 Multiply both sides by 5 to get: sum of all 5 numbers in set A = 215
QUANTITY A: The value of x if the average of x and the 5 numbers in dataset A is 46 (215 + x)/6 = 46 Multiply both sides by 6 to get: 215 + x = 276 Solve: x = 61
The average of the 10 numbers in datasets A and B combined is 52. (sum of all 10 numbers)/10 = 52 Multiply both sides by 10 to get: sum of all 10 numbers = 520 In other words: (sum of the 5 numbers in set A) + (sum of the 5 numbers in set B)= 520 We get: 215 + (sum of the 5 numbers in set B)= 520 Subtract 215 from both sides to get: sum of the 5 numbers in set B = 305 AVERAGE of the 5 numbers in set B = 305/5 = 61
Re: Dataset A consists of 5 numbers, which have an average (arit
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10 Sep 2021, 04:10
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For A,
(x + 43*5) / 6 = 46 => x = 61
For B,
(Sum of Dataset A values + Sum of Dataset B values ) / 10 = 52 => 43*5 + Sum of Dataset B values = 520 => Sum of Dataset B values = 305 => Average value of Dataset B = 305/5 = 61
Re: Dataset A consists of 5 numbers, which have an average (arit
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28 Nov 2024, 00:43
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Re: Dataset A consists of 5 numbers, which have an average (arit [#permalink]