GreenlightTestPrep wrote:
Attachment:
Z04.png
If
ABC is an equilateral triangle, and
BC=4√3, what is the approximate length
of one side of square
WXYZ?
A) 1.9
B) 2.9
C) 3.2
D) 4.1
E) 4.6
Since
ABC is an
equilateral triangle, we know the following angles are 60° each.
Also, let's let n = the length of each side of the
square
Since BWX is also an
equilateral triangle, we know that all 3 sides have length n:

Since
BC=4√3, and since
BX=n, we know that side
XC=4√3−n
At this point, we can see that triangle XYC is a special 30-60-90 right triangle.

When we compare
∆XYC with the
base 30-60-90 triangle, we can compare corresponding sides to create the following equation: (
4√3 - n)/
2 =
n/
√3Cross multiply to get: (√3)(4√3 - n)= (2)(n)
Simplify to get: 12 - (√3)n = 2n
Add (√3)n to both sides to get: 12 = 2n + (√3)n
Factor right side to get: 12 = n(2 + √3)
Divide both sides by (2 + √3) to get: n = 12/(2 + √3)
PRO TIP #1: By test day, all students should have the following approximations memorized:
√2 ≈ 1.4
√3 ≈ 1.7
√5 ≈ 2.2
So, 12/(2 + √3) ≈ 12/(2 + 1.7) ≈ 12/3.7
PRO TIP #2: We need not calculate the actual value of 12/
3.7Instead, notice that 12/
3 = 4 and 12/
4 = 3
Since
3.7 is BETWEEN
3 and
4, we now that 12/
3.7 must be between 3 and 4
In other words, 12/
3.7 = 3.something.
Answer: C
Cheers,
Brent