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A certain train travels 150 miles in h hours at the average
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25 Nov 2019, 08:10
25 Nov 2019, 08:10
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81% (01:17) correct
18% (01:42) wrong based on 98 sessions
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A certain train travels 150 miles in h hours at the average rate of m miles per hour.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The number of hours required for the train to travel 320 miles at the average rate of \(2m\) miles per hour |
\(h\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: A certain train travels 150 miles in h hours at the average
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25 Nov 2019, 19:41
25 Nov 2019, 19:41
After calculating, getting for A is ( h + some of values), and now put any value for h or get rid of h, you will get A always bigger then B.
What if we take negative value for "h", then B must be bigger but (N:B: Remember distance never be a minus value/sign. )
So, Answer A.
What if we take negative value for "h", then B must be bigger but (N:B: Remember distance never be a minus value/sign. )
So, Answer A.
Re: A certain train travels 150 miles in h hours at the average
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26 Nov 2019, 05:15
26 Nov 2019, 05:15
2
Distance = rate x time
In this case D=150, r=m, t=h.
So 150=mh => h=150/m
In quantity A 320=2mh So h=320/2m so h=160/m
Answer A
In this case D=150, r=m, t=h.
So 150=mh => h=150/m
In quantity A 320=2mh So h=320/2m so h=160/m
Answer A
