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0 < a < 3 3 < b < 0 a and b are integers.

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Carcass
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0 < a < 3 3 < b < 0 a and b are integers. [#permalink] New post   27 Jan 2020, 03:30
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\(0 < a < 3\)

\(−3 < b < 0\)

a and b are integers.

Quantity A
Quantity B
a+b
a-b


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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B
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GreenlightTestPrep
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Re: 0 < a < 3 3 < b < 0 a and b are integers. [#permalink] New post   27 Jan 2020, 06:31
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Carcass wrote:
\(0 < a < 3\)
\(−3 < b < 0\)

a and b are integers.

Quantity A
Quantity B
a+b
a-b




We can solve this question using matching operations

Given:
Quantity A: \(a+b\)
Quantity B: \(a-b\)

Subtract \(a\) from both quantities to get:
Quantity A: \(b\)
Quantity B: \(-b\)

Add \(b\) to both quantities to get:
Quantity A: \(2b\)
Quantity B: \(0\)

Divide both quantities by \(2\) to get:
Quantity A: \(b\)
Quantity B: \(0\)

From the given information, \(−3 < b < 0\), we're told that \(b\) is negative
As such, Quantity B must be greater.

Answer: B

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Re: 0 < a < 3 3 < b < 0 a and b are integers. [#permalink] New post   29 Jan 2020, 06:39
1
1
0<a<3 -(1)
-3<b<0 -(2)

Add 1 & 2
-3< a + b < 3

Also, multiply -1 with (2)
Now, 0<-b<3 - (3)
Add 1 & 3

0<a-b<6

Hence, clearly answer is D
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Re: 0 < a < 3 3 < b < 0 a and b are integers. [#permalink] New post   01 Mar 2020, 22:20
so is the answer b or d here?
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Re: 0 < a < 3 3 < b < 0 a and b are integers. [#permalink] New post   02 Mar 2020, 04:39
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The answer is B as for the OA and the explanation provided by Brent.

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Re: 0 < a < 3 3 < b < 0 a and b are integers. [#permalink] New post   24 Sep 2021, 23:11
Choosing numbers, makes the answer definitely D.

Posted from my mobile device
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Kimberly99
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Re: 0 < a < 3 3 < b < 0 a and b are integers. [#permalink] New post   14 Feb 2023, 01:22
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Hi Brent GreenlightTestPrep, Is below calculation the right way? Thanks Brent

Adding a+b

0 < a < 3
−3 < b < 0
-------------
-3<a+b<3-----1

Subtrating a-b

0 < a < 3
−3 < b < 0
-------------
3<a-b<3-----2

Compare 1& 2, B is bigger.
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Re: 0 < a < 3 3 < b < 0 a and b are integers. [#permalink] New post   14 Feb 2023, 04:03
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Kimberly99 wrote:
Hi Brent GreenlightTestPrep, Is below calculation the right way? Thanks Brent

Adding a+b

0 < a < 3
−3 < b < 0
-------------
-3<a+b<3-----1

Subtrating a-b

0 < a < 3
−3 < b < 0
-------------
3<a-b<3-----2

Compare 1& 2, B is bigger.


It is correct

In this case manipulating is good but picking number is a little bit faster

a is either 1 or2

b is either -1 or -2

Substitute and B is always bigger than A
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Re: 0 < a < 3 3 < b < 0 a and b are integers. [#permalink] New post   16 Feb 2023, 05:11
Thanks Carcass for confirmation and noted.
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Re: 0 < a < 3 3 < b < 0 a and b are integers. [#permalink] New post   31 Mar 2024, 14:08
Hello from the GRE Prep Club BumpBot!

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Re: 0 < a < 3 3 < b < 0 a and b are integers. [#permalink]
31 Mar 2024, 14:08
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