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A brown flask contains a concoction that is 20% alcohol.
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26 Jun 2020, 00:55
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A brown flask contains a concoction that is 20% alcohol. A red flask contains a concoction with an unknown amount of alcohol. An equal amount of both flasks is poured into an empty jug. If the resulting mixture has an alcohol concentration that is 30% greater than the alcohol concentration of the brown flask, what percent alcohol did the red flask originally contain?
Re: A brown flask contains a concoction that is 20% alcohol.
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26 Jun 2020, 06:22
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The brown flask contains 20% alcohol, the final mixture has an alcohol content thats 30% greater than the brown flask concentration. 20 * 1.30 = 26% - final alcohol concentration (30% greater than starting 20%)
Now basically if we combine 2 alcoholic mixtures in the equal amounts the resulting mixture will have the alcohol content of the average between the two percentages. (ex. if the two jugs have 20% and 22%, the combined mixture will be 21%)
To get 26% final concentration we must then have 32% alcohol in the red flask ([20+32]/2 = 26%) So the answer is C
How can you say 30% of 20% of the volume in the flask by just 30% of 20 is 6? We are not provided with the information about the total liquid capacity right? Sorry if am wrong here. I tried hard , but without the capacity or volume mentioned was stuck half way through. Seeing your solution I was puzzled if am going wrong anywhere. pls clarify
Re: A brown flask contains a concoction that is 20% alcohol.
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22 Jul 2023, 02:01
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Re: A brown flask contains a concoction that is 20% alcohol. [#permalink]