Last visit was: 25 Nov 2024, 08:36 It is currently 25 Nov 2024, 08:36

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 30022
Own Kudos [?]: 36391 [4]
Given Kudos: 25928
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 30022
Own Kudos [?]: 36391 [0]
Given Kudos: 25928
Send PM
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12197 [0]
Given Kudos: 136
Send PM
avatar
Intern
Intern
Joined: 07 Jun 2020
Posts: 7
Own Kudos [?]: 6 [3]
Given Kudos: 2
Send PM
Re: A committee of three people is to be chosen from four marrie [#permalink]
3
Carcass wrote:
A committee of three people is to be chosen from four married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?

A. 16
B. 24
C. 26
D. 30
E. 32




Let's Suppose we have 4 Couples.

Call them

M1 F1
M2 F2
M3 F3
M4 F4

Now, as per question statement, apply FCP:

we have three Slots

____ ____ ____


How many choices do we have for Slot 1? 8 Choices because any of the person from a couple can be selected for 1st Slot

=> 8

Now move on to the 2nd Slot. How many choices do we have for the 2nd Slot? Let's say we have selected M1 for Slot 1. Now, F1 can't be selected for 2nd Slot because of the restriction in the question statement.

For 2nd Slot, total number of choices will be

8 6

Similary, for 3rd Slot, Let's say we have selected F2 for Slot 2. Now, M2 can't be selected for 3rd Slot because of the restriction in the question statement.

Since, M1 and F2 are already selected by us for slot 1 and 2 respectively, F1 and M2 can't be selected for third slot, and M1 and F2 are already on the committee. We are left with only four choices which are: M3 F3 M4 F4

So, for Slot 3

8 6 4

Now, divide the whole expression by 3! to remove the repeatitions.

=> 8*6*4/6
=> 32

Hence E!
Intern
Intern
Joined: 05 Feb 2024
Posts: 26
Own Kudos [?]: 17 [1]
Given Kudos: 151
Send PM
Re: A committee of three people is to be chosen from four marrie [#permalink]
1
Take any 3 out of these 4 couples in 4C3 ways,

Now, from each couple you've to choose 1 person to represent. i.e., 2C1 for each couple and we have to choose one person per couple out of the three couples we've chosen above,

Therefore, the total number of ways in which the committee can be formed is - 4C3*2C1*2C1*2C1= 4*2*2*2 = 32 ways

Answer is E

Thanks

Sincerely

Daksh Kumar
Prep Club for GRE Bot
Re: A committee of three people is to be chosen from four marrie [#permalink]
Moderators:
GRE Instructor
84 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne