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A number is randomly chosen from the first 100 positive inte
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26 Aug 2020, 18:17
26 Aug 2020, 18:17
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Question Stats:
95% (00:42) correct
4% (00:36) wrong based on 21 sessions
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A number is randomly chosen from the first 100 positive integers. What is the probability that it is a multiple of 3?
A: 32/100
B: 33/100
C: 1/3
D: 34/100
E: 2/3
Error in this Manhattan solution to Ch23/Q2?
Manhattan solution is B. But I selected D. My thinking is that in addition to 99/3 = 33 numbers that are multiple of 3, there is also 1 which is a multiple of every number!! Am I missing something? thank you for your help
Edit: it's question 3 not 2
A: 32/100
B: 33/100
C: 1/3
D: 34/100
E: 2/3
Error in this Manhattan solution to Ch23/Q2?
Manhattan solution is B. But I selected D. My thinking is that in addition to 99/3 = 33 numbers that are multiple of 3, there is also 1 which is a multiple of every number!! Am I missing something? thank you for your help
Edit: it's question 3 not 2
Re: A number is randomly chosen from the first 100 positive inte
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26 Aug 2020, 20:27
26 Aug 2020, 20:27
1
Expert Reply
Thanks for posting. You may want to check this discussoin:
https://gre.myprepclub.com/forum/a-number- ... 10216.html
I think many people choose D, and that's why that 34 is there. However, the question is about multiples of 3. I don't see how 1 fits in there. These are not factors but multiples (numbers that are divisible by 3.... hope it helps). If not, ask away.
Thx.
BB
https://gre.myprepclub.com/forum/a-number- ... 10216.html
I think many people choose D, and that's why that 34 is there. However, the question is about multiples of 3. I don't see how 1 fits in there. These are not factors but multiples (numbers that are divisible by 3.... hope it helps). If not, ask away.
Thx.
BB
Re: A number is randomly chosen from the first 100 positive inte
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27 Aug 2020, 04:08
27 Aug 2020, 04:08
1
Expert Reply
Moved under the right section. Please follow the rules for posting
https://gre.myprepclub.com/forum/rules-for ... -1083.html
Back to the question
Given : A number is randomly chosen from the first 100 positive integers.
Question : What is the probability that it is a multiple of 3?
We need to find the number of multiples of 3 in first 100 POSITIVE integers.
By AP we have
Tn = a + (n-1)*d (where, Tn = 99; a= 3; d =3)
99 = 3 + (n-1)* 3
96 = (n-1)* 3
32 = (n-1)
n = 33
Therefore, the probability that chosen number in first 100 is a multiple of 3 is given by
= No. of favorable outcomes / Total no. of outcomes
= 33 / 100
Answer Option B is Correct.
Regrds
https://gre.myprepclub.com/forum/rules-for ... -1083.html
Back to the question
Given : A number is randomly chosen from the first 100 positive integers.
Question : What is the probability that it is a multiple of 3?
We need to find the number of multiples of 3 in first 100 POSITIVE integers.
By AP we have
Tn = a + (n-1)*d (where, Tn = 99; a= 3; d =3)
99 = 3 + (n-1)* 3
96 = (n-1)* 3
32 = (n-1)
n = 33
Therefore, the probability that chosen number in first 100 is a multiple of 3 is given by
= No. of favorable outcomes / Total no. of outcomes
= 33 / 100
Answer Option B is Correct.
Regrds
