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A pyramid has a square base of 6 cm, and the four lateral faces are
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06 Mar 2021, 23:56
OA Explanation
T.S.A of the Square Pyramid = Area of the Square base + \(4\) x (Area of equilateral faces)
Area of equilateral triangle with each side \(a\) = \(\frac{\sqrt{3}}{4}a^2 = \frac{\sqrt{3}}{4}6^2 = 9\sqrt{3}\)
Area of Square base with each side \(a\) = \(a^2 = 6^2 = 36\)
Therefore, T.S.A of the Square Pyramid = \(36\) + \(4(9\sqrt{3}\)) = \(36 + 36\sqrt{3}\)
Hence, option B