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Joined: 19 Nov 2020
Posts: 326
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GRE 1: Q160 V152
At a certain car dealership, the probability of selecting ...
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15 Aug 2021, 05:11
15 Aug 2021, 05:11
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Question Stats:
39% (03:16) correct
60% (03:08) wrong based on 23 sessions
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At a certain car dealership, the probability of selecting a car of red color by customer is 1/6. The probability of selecting a car of X model is 5/13. Which of the following could not be the probability of selecting a car, which is either of red color or X model or both?
(A) 3/8
(B) 5/11
(C) 5/13
(D) 7/13
(E) 8/15
Very hard
Source text edited/modified
(A) 3/8
(B) 5/11
(C) 5/13
(D) 7/13
(E) 8/15
Very hard
Source text edited/modified
Re: At a certain car dealership, the probability of selecting ...
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17 Aug 2021, 03:11
17 Aug 2021, 03:11
A
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Posted from my mobile device
Re: At a certain car dealership, the probability of selecting ...
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20 Aug 2021, 15:56
20 Aug 2021, 15:56
2
Let's say, there are 78 cars. So, red cars will be= 13, and other colored cars=65.
Also, X model cars will be 30, and other model cars will be 48.
To solve this, at first, we need to calculate the range of n(Red U X). The lowest value will happen when all the red cars are already in model X which is 30. And the highest value will happen when no red cars are in model X and n(Red U X) = 43.
So the range of probability = 30/78 < P(Red U X) < 43/78. Only answer choice (a) violates this.
Also, X model cars will be 30, and other model cars will be 48.
To solve this, at first, we need to calculate the range of n(Red U X). The lowest value will happen when all the red cars are already in model X which is 30. And the highest value will happen when no red cars are in model X and n(Red U X) = 43.
So the range of probability = 30/78 < P(Red U X) < 43/78. Only answer choice (a) violates this.
