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During the recruitment process, an organization either appoints 10 new
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12 Jul 2023, 00:58
12 Jul 2023, 00:58
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Question Stats:
57% (01:30) correct
42% (01:32) wrong based on 14 sessions
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During the recruitment process, an organization either appoints 10 new employees or fires 6 existing ones. If in a certain month there was no change in the number of employees and the recruitment happened at least once, what could be the minimum number of recruitment processes that took place?
A. 5
B. 8
C. 13
D. 16
E. None of the above
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A. 5
B. 8
C. 13
D. 16
E. None of the above
Post A Detailed Correct Solution For The Above Questions And Get Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE NUMBER PROPERTIES
Re: During the recruitment process, an organization either appoints 10 new
[#permalink]
14 Jul 2023, 12:19
14 Jul 2023, 12:19
3
So it is mentioned that there is no change in the number of employees and the recruitment has happened at least once.
the equation for the problem can be written as 10x-6y=0.
x for the number of recruitment leading to addition of new 10 employees.
y is the number of times the firing of 6 people happens.
( minus because of the firing of employees i.e. no. of employees decreases and 0 because it is mentioned that there is no change irrespective of the recruitment.)
x=0,y=0 cannot be the solution as it is mentioned that recruitment happens at least once.
Now, we want to find the minimum number of recruitment process with the equation 10x=6y.
To find the minimum number for recruitment we have to find LCM for the above equation.
LCM of 10 and 6 is 30.
Therefore, x has to be 3 and y has to be 5.
To find the total number of recruitment process we have to add x and y. So the ans 8.
Let me know if this is the right logic. Ty!
the equation for the problem can be written as 10x-6y=0.
x for the number of recruitment leading to addition of new 10 employees.
y is the number of times the firing of 6 people happens.
( minus because of the firing of employees i.e. no. of employees decreases and 0 because it is mentioned that there is no change irrespective of the recruitment.)
x=0,y=0 cannot be the solution as it is mentioned that recruitment happens at least once.
Now, we want to find the minimum number of recruitment process with the equation 10x=6y.
To find the minimum number for recruitment we have to find LCM for the above equation.
LCM of 10 and 6 is 30.
Therefore, x has to be 3 and y has to be 5.
To find the total number of recruitment process we have to add x and y. So the ans 8.
Let me know if this is the right logic. Ty!
Re: During the recruitment process, an organization either appoints 10 new
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23 Sep 2024, 13:03
23 Sep 2024, 13:03
1
Why have we considered 5 here? That stands for firing. Isn't the recruitment done thrice?
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