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Re: An artist is planning on mixing together any number of diffe [#permalink]
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indiragre18 wrote:
For 8 colors, no. of mixtures the artist makes must be 8C2+8C3+8C4+8C5+8C6+.... which is (2^8 - 8C0 - 8C1)
For 9 colors, the number is 2^9 - 9C0 - 9C1 which is > 500.
Hence, the number of colors on palette is EIGHT!


How do you know that 8C2+8C3+8C4+8C5+8C6+.... = (2^8 - 8C0 - 8C1) ?
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Re: An artist is planning on mixing together any number of diffe [#permalink]
it is mentioned that at least 2 colors so we cannot ignore the possibilities of 8c3+8c4+...............
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Re: An artist is planning on mixing together any number of diffe [#permalink]
TAKE THREE COLRS RED BLUE GREEN ....(RGB)...RECALL SETS CHAPTER
NUMBER OF SUBSET WITH 3 ELEMENTS IS GIVEN BY 2^3=8 SUBSET...THIS INCLUDES A NULL SET WHERE NO COLOR IS CHOSEN...USE THIS ANALOGY
CHOOSING NO COLRS FROM SET(NC0=1) + CHOOSING ONE COLR (NC1=N)+(X=TWO COLOR+THREE COLOR.....)=2^N
NOW X IS GIVEN AS LESS THAN 500 SO JUST PUT THESE VALUES AND SOLVE
1+N+X=2^N
X=2^N-1-N
500<2^N-1-N
FROM OPTIONS ONLY SUITABLE VALUE IS 8..SO N=8
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Re: An artist is planning on mixing together any number of diffe [#permalink]
not clear with wordings as we can mix 2 colors or 3 colors and so on ...
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Re: An artist is planning on mixing together any number of diffe [#permalink]
Hello from the GRE Prep Club BumpBot!

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Re: An artist is planning on mixing together any number of diffe [#permalink]
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