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Two dogsled teams raced across a 300 mile course in Wyoming. Team A fi

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Two dogsled teams raced across a 300 mile course in Wyoming. Team A fi [#permalink] New post   31 Mar 2022, 09:49
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Two dogsled teams raced across a 300 mile course in Wyoming. Team A finished the course in 3 fewer hours than team B. If team A's average speed was 5 mph greater than team B's, what was team B's average mph?

A. 12
B. 15
C. 18
D. 20
E. 25
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D
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D
GeminiHeat
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Joined: 20 Feb 2017
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Re: Two dogsled teams raced across a 300 mile course in Wyoming. Team A fi [#permalink] New post   08 Apr 2022, 03:24
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Explanation

\(\frac{300}{s}-\frac{300}{s+5}=3\)

\(=\frac{(300s+1500-300s)}{s(s+5)}=3\)

\(=s^2+5s-500=0\)

\(=s^2+25s-20s-500=0\)

\(s=20\)

Ans. D
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Re: Two dogsled teams raced across a 300 mile course in Wyoming. Team A fi [#permalink]
08 Apr 2022, 03:24
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