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GRE Two tangents are drawn.png [ 81.09 KiB | Viewed 60 times ]
In the figure above, two tangents $\(\mathrm{PA} \& \mathrm{~PB}\)$ intersect at point P and form an angle of x degrees. Also the angle formed at the centre is 65 degrees.
As radius is always perpendicular on tangent, we get angle $\(\mathrm{OBP}=\)$ angle $\(\mathrm{OAP}=90\)$ degrees each.
Now, in quadrilateral PAOB , we get angle $\(\mathrm{APB}=\mathrm{x}^{\circ}=360^{\circ}-\left(65^{\circ}+90^{\circ}+90^{\circ}\right)=360^{\circ}-245^{\circ}= 115^{\circ}\)$ (Sum of the angles of a quadrilateral is 360 degrees)
Hence the answer is (D).