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Victor is walking at a rate of 1 mile every 17 minutes : Numeric Entry Question

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Re: Victor is walking at a rate of 1 mile every 17 minutes [#permalink]
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My bad guys! Answer is 1.28. Changed it!

Thanks for pointing out!
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Re: Victor is walking at a rate of 1 mile every 17 minutes [#permalink]
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Explanation

First, find the two people’s rates in terms of miles per hour (mph). Victor’s rate equals distance over time, or 1 mile over \(\frac{17}{60}\)hours, which equals approximately 3.529 mph.

Calculating Sarah’s speed using the same steps gives you her rate, 4.286 mph. When added, the two rates become their combined rate of 7.815 mph. When you divide 10 miles by 7.815, the answer is approximately 1.28 hours until they meet.
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Re: Victor is walking at a rate of 1 mile every 17 minutes [#permalink]
3
s1=1/17
s2=1/14
t=10/(1/17+1/14)
=2380/31
=1.279
=1.28
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Re: Victor is walking at a rate of 1 mile every 17 minutes [#permalink]
divyavivek wrote:
Hi sandy,


My answer is also not 10.how it is possible?
my explanation is that,both of them together can cover 2.21 miles in every 17 minutes(for victor 1 miles in 17 minutes and for saraha approximately 1.21 miles in 17 minutes([1/14]*17=1.21)).
therefore both of them together can cover 10 miles in 76.92 minutes=1.28 hr=1.3 hr
or in another words both of them took 1.3 hr to meet each other


if it isn't too much trouble, what is the logic behind combining the two rates and dividing 10 by the combined rates? I don't understand how those steps connect to the logic of the question. Thanks
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Re: Victor is walking at a rate of 1 mile every 17 minutes [#permalink]
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Re: Victor is walking at a rate of 1 mile every 17 minutes [#permalink]
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