25. The equation of the parabola is y = (x - h) 2 + k. The standard equation of a parabola in vertex form is y = a(x - h) 2 + k, where the vertex is (h, k). (Since the equation of this particular parabola does not have constant a, a must be equal to 1.)
Using y = (x - h) 2 + k and the vertex (2, 0) shown in the graph:
y = (x - 2) 2 + 0
y = (x - 2) 2

Since (-3, n) is a point on the parabola, plug in -3 and n for x and y:
n = (-3 - 2) 2
n = (-5) 2
n = 25

The equation of the given parabola is y = (x – h)2 + k. The standard
equation of a parabola in vertex form is y = a(x – h)2 + k, where the vertex is
(h, k). (Since the equation of this particular parabola does not have constant a,
a must be equal to 1.)
Using y = (x – h)2 + k and the vertex (2, 0) shown in the graph:
y = (x – 2)2 + 0
y = (x – 2)2
Since (–3, n) is a point on the parabola, plug in –3 and n for x and y,
respectively:
n = (–3 – 2)2
n = (–5)2
n = 25

This should not be difficult, as \(y = (x - h)^2 + k\) is minized when \(x=2\) and \(y=0\).

\(y = (x - h)^2 + k\) is minimized if \((x - h)^2=0\) and k should be anything but not negative. Here, only \(k=0\) results in the minimum value of \(y = (x - h)^2 + k\).

Hence, plugging (-3,n) into \(y = (x - h)^2 + k\), we obtain \(n = (-3 - 2)^2 + 0\) and \(n=25\)

Answer is 25