Carcass wrote:
If the sum of the first 500 positive integers is k, what is the sum of the first 1000 positive integers in terms of k?
Average of first n cons. integers =
(Last+First)2 Sum = (Average)(number of terms)
k = Sum of first 500 +ve integers =
(500+1)2(500)=(501)(250)Sum of first 1,000 +ve integers =
(1,000+1)2(1,000)=(1,001)(500)Rewrite
(1,001)(500) as
(501+500)(250+250)(501)(250)+(501)(250)+(500)(250)+(500)(250)k+k+2(500)(250)2k+(500)(500)2k+250,000