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Re: There are 5 chairs. Bob and Rachel want to sit such that Bob is always [#permalink]
4!(1!)
=24

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Re: There are 5 chairs. Bob and Rachel want to sit such that Bob is always [#permalink]
correct answer is....
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Re: There are 5 chairs. Bob and Rachel want to sit such that Bob is always [#permalink]
1
Hello,

What's the actual answer to this type of question.

I get 24.

Why is the law of symmetry producing another answer

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Re: There are 5 chairs. Bob and Rachel want to sit such that Bob is always [#permalink]
Expert Reply
Let the chairs from left to right be :
A B C D E

If:
(i) Rachel is at A, possible arrangements = 0
(ii) Rachel is at B, possible arrangements = 1
(iii) Rachel is at C, possible arrangements = 2
(iv) Rachel is at D, possible arrangements = 3
(v) Rachel is at E, possible arrangements = 4

Total = 1+2+3+4 = 10
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Re: There are 5 chairs. Bob and Rachel want to sit such that Bob is always [#permalink]
Carcass wrote:
Let the chairs from left to right be :
A B C D E

If:
(i) Rachel is at A, possible arrangements = 0
(ii) Rachel is at B, possible arrangements = 1
(iii) Rachel is at C, possible arrangements = 2
(iv) Rachel is at D, possible arrangements = 3
(v) Rachel is at E, possible arrangements = 4

Total = 1+2+3+4 = 10



I see the difference now. So Left of Rachel don't necessarily mean JUST BEFORE Rachel.

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Re: There are 5 chairs. Bob and Rachel want to sit such that Bob is always [#permalink]
Carcass wrote:
Let the chairs from left to right be :
A B C D E

If:
(i) Rachel is at A, possible arrangements = 0
(ii) Rachel is at B, possible arrangements = 1
(iii) Rachel is at C, possible arrangements = 2
(iv) Rachel is at D, possible arrangements = 3
(v) Rachel is at E, possible arrangements = 4

Total = 1+2+3+4 = 10

This assumes that the all chairs are similar to each other. If all chairs weren't the same, then the answer would be 4!
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