GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
A is the center of the top face of the right circular cylind
[#permalink]
25 Nov 2020, 09:33
25 Nov 2020, 09:33
Expert Reply
5
Bookmarks
00:00
Question Stats:
55% (02:40) correct
45% (02:16) wrong based on 20 sessions
Hide Show timer Statistics
Attachment:
GRE A is the center of the top face of the right circular cylinder.jpg [ 22.98 KiB | Viewed 2682 times ]
\(A\) is the center of the top face of the right circular cylinder in the figure above. If the degree measure of \(∠BAC\) is four times that of \(∠ACB\), and the height of the cylinder is equal to the diameter of its base, then the volume of the shaded region is what fraction of the volume of the entire cylinder?
Show: :: OA
\(\frac{1}{3}\)
Re: A is the center of the top face of the right circular cylind
[#permalink]
28 Nov 2020, 23:58
28 Nov 2020, 23:58
1/3!
Intern
Joined: 22 Jul 2019
Posts: 14
Given Kudos: 75
Location: United States
Re: A is the center of the top face of the right circular cylind
[#permalink]
29 Nov 2020, 04:45
29 Nov 2020, 04:45
2
lets say ∠ACB=x, therefore ∠BAC=4x, ∠ABC=x (△ABC is Isosceles)
x+4x+x=180° , x= 30° ,therefore ∠BAC=120°
Volume proportion of shaded region to entire Cylinder= 120/360 =1/3
x+4x+x=180° , x= 30° ,therefore ∠BAC=120°
Volume proportion of shaded region to entire Cylinder= 120/360 =1/3
