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Re: In the figure above, what is x? [#permalink]
100
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Re: In the figure above, what is x? [#permalink]
IlCreatore wrote:
Taking into consideration the quadrilateral, getting rid of the oblique line that is just to make the question trickier, we have that its internal angles must sum to 360. Thus, we can say that 2x + 110 + 50 = 360 and thus x = 100.


A creative and elegant solution, who says you can't remove lines as needed. Definitely not used to these kinds of problems from college but I love it!
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Re: In the figure above, what is x? [#permalink]
great question
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Re: In the figure above, what is x? [#permalink]
pranab01 wrote:

Now adding the angles in the polygon we have = 110 +2x +(180-a)+(180-b) =540

or 2x = 70+a+b
or x = 200/2 = 100 (since in the triangle of angle 50,a,b we have a+b+50 =180 or a+b = 130)

I cannot find a and b.
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Re: In the figure above, what is x? [#permalink]
pranab01 wrote:
Carcass wrote:

In the figure above, what is x?

enter your value

Show: :: OA
100


Another alternative to the problem

If we consider the 5 sided polygon in the center and sum of the interior angles will be (n-2)*180 = (5-2)*180=540 degree.

Now adding the angles in the polygon we have = 110 +2x +(180-a)+(180-b) =540

or 2x = 70+a+b



or x = 200/2 = 100 (since in the triangle of angle 50,a,b we have a+b+50 =180 or a+b = 130)



Attachment:
#GREpracticequestion In the figure above, what is x.jpg


I dont think we can assume the sum of the opposite angles of a and b even with one of the internal degree measurements.
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Re: In the figure above, what is x? [#permalink]
Taking into consideration the quadrilateral, getting rid of the oblique line that is just to make the question trickier, we have that its internal angles must sum to 360. Thus, we can say that 2x + 110 + 50 = 360 and thus x = 100.
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Re: In the figure above, what is x? [#permalink]
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