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a, b, and c are consecutive integers such that a < b < c < 4
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02 Sep 2018, 07:12
02 Sep 2018, 07:12
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a, b, and c are consecutive integers such that a < b < c < 4.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The range of a, b, and c |
The average of a, b, and c |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Re: a, b, and c are consecutive integers such that a < b < c < 4
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16 Nov 2018, 12:59
16 Nov 2018, 12:59
1
sandy wrote:
a, b, and c are consecutive integers such that a < b < c < 4.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The range of a, b, and c |
The average of a, b, and c |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Since the values (a, b and c) are 3 consecutive integers, then the range must be 2.
We know this, because b is 1 greater than a, which means c is 2 greater than a
Range = c - a = 2
As far as the average is concerned, we know very little. So, let's TEST some possible cases:
CASE A: a, b and c COULD equal 1, 2 and 3 (respectively), in which case the average = (1 + 2 + 3)/3 = 2
So, we get:
Quantity A: 2
Quantity B: 2
In this case, the two quantities are EQUAL
CASE B: a, b and c COULD equal 0, 1 and 2 (respectively), in which case the average = (0 + 1 + 2)/3 = 1
So, we get:
Quantity A: 2
Quantity B: 1
In this case, Quantity A IS GREATER
Answer: D
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Joined: 07 Aug 2016
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GRE 1: Q166 V156
Re: a, b, and c are consecutive integers such that a < b < c < 4
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19 Nov 2018, 15:46
19 Nov 2018, 15:46
1
Let a, b, c be 1,2,3 respectively
The range would be 3 - 1 = 2
The average = 6/3 = 2 we get once case where they are equal.
Try a = - 5 b = -4 and c = -3
The range is -3 - (-5) = -3 + 5 = 2
The average is -5 -4 -3 = -12/3 = -4
Range is larger than average. This leads to answer choice D
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The range would be 3 - 1 = 2
The average = 6/3 = 2 we get once case where they are equal.
Try a = - 5 b = -4 and c = -3
The range is -3 - (-5) = -3 + 5 = 2
The average is -5 -4 -3 = -12/3 = -4
Range is larger than average. This leads to answer choice D
Posted from my mobile device
