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p and w are single-digit prime numbers such that p + w < 6.
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02 Sep 2018, 07:30
02 Sep 2018, 07:30
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72% (00:43) correct
27% (01:01) wrong based on 79 sessions
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p and w are single-digit prime numbers such that \(p + w < 6\). \(p^2\) is odd.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
w |
3 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: p and w are single-digit prime numbers such that p + w < 6.
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03 Sep 2018, 10:21
03 Sep 2018, 10:21
1
sandy wrote:
p and w are single-digit prime numbers such that \(p + w < 6\). \(p^2\) is odd.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
w |
3 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Prime numbers are 2,3,5,7...etc
Given \(p^2\) is odd , so it has be from 3,5,7.... other than 2.
We are told that \(p + w < 6\)
Least value of p can be 3 and w has to be 2 or else result will be greater than 6.
So w has to be 2.
col b > a.
B.
Re: p and w are single-digit prime numbers such that p + w < 6.
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25 Jun 2021, 13:10
25 Jun 2021, 13:10
1
Since the question doesn't specify if the numbers are negative, why is the answer not D - cannot be solved? For example: If p = -5, then it is still a single digit prime, could still result in an odd square, and could satisfy the inequality of -5 + w <6. In this example, w could equal 3 and then the solution would be equal. Since there are multiple solutions, shouldn't the answer to this question be D?
