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Sum of the angles (in degrees) in a pentagon

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Carcass
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Sum of the angles (in degrees) in a pentagon [#permalink] New post   24 Sep 2018, 11:52
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Quantity A
Quantity B
Sum of the angles (in degrees) in a pentagon
500°


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Official Answer
A
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GreenlightTestPrep
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Re: Sum of the angles (in degrees) in a pentagon [#permalink] New post   24 Sep 2018, 13:13
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Carcass wrote:
Quantity A
Quantity B
Sum of the angles (in degrees) in a pentagon
500°


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Useful rule: the sum of the angles in an n-sided polygon = (n - 2)(180°)

A pentagon has 5 sides
So, the sum of the angles = (5 - 2)(180°)
= (3)(180°)
= 540°

We get:
Quantity A: 540°
Quantity B: 500°

Answer: A

Cheers,
Brent
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AE
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Re: Sum of the angles (in degrees) in a pentagon [#permalink] New post   18 Jan 2019, 06:41
(5 - 2)(180°)
= (3)(180°)
= 540°
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Re: Sum of the angles (in degrees) in a pentagon [#permalink] New post   18 Jan 2019, 06:42
AE wrote:
(5 - 2)(180°)
= (3)(180°)
= 540°

Hence Answer A
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Dev_ben
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Re: Sum of the angles (in degrees) in a pentagon [#permalink] New post   17 Mar 2019, 00:41
GreenlightTestPrep wrote:
Carcass wrote:
Quantity A
Quantity B
Sum of the angles (in degrees) in a pentagon
500°


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


Useful rule: the sum of the angles in an n-sided polygon = (n - 2)(180°)

A pentagon has 5 sides
So, the sum of the angles = (5 - 2)(180°)
= (3)(180°)
= 540°

We get:
Quantity A: 540°
Quantity B: 500°

Answer: A

Cheers,
Brent





the question does not state if its a regular pentagon. how can we be so sure if the sum is greater than 500 degrees?
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GREsucks
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Re: Sum of the angles (in degrees) in a pentagon [#permalink] New post   01 Jun 2019, 04:10
Carcass wrote:
Quantity A
Quantity B
Sum of the angles (in degrees) in a pentagon
500°


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.


The question doesn't mention which angles - interior or exterior!!
Can we assume it to be interior?
It's a tricky question in QC category where assumption or lack of info can change the answer.
Don't know what to do here.... Can anybody suggest?
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Re: Sum of the angles (in degrees) in a pentagon [#permalink] New post   01 Jun 2019, 09:10
Expert Reply
Is nothing is stated about external angle or else, you should always think about INTERNAL angles.

If you talk about a triangle and nothing is stated I do think is fair to cast our assumption on its internal angles which the sum is 180°

regards
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Sid23
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Re: Sum of the angles (in degrees) in a pentagon [#permalink] New post   02 Jun 2019, 02:03
nice
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Madhavi1990
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Re: Sum of the angles (in degrees) in a pentagon [#permalink] New post   27 Jul 2020, 06:49
Qty A--> Pentagon (internal) angles add up to 540. Kudos if you like this post
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IsaacKim808
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Re: Sum of the angles (in degrees) in a pentagon [#permalink] New post   27 Jul 2020, 16:41
Draw out a pentagon and basically it's a triangle sitting on top of a square.

Degrees of a triangle + Degrees of a square

180 + 360 = 540 degrees.

Therefore answer is A
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