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Which is greater: Sum of the integers from 1 to 40 inclusive
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Updated on: 30 Dec 2022, 08:37
Updated on: 30 Dec 2022, 08:37
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Question Stats:
52% (00:41) correct
47% (00:53) wrong based on 87 sessions
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Quantity A |
Quantity B |
Sum of the integers from 1 to 40 inclusive |
800 |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Re: Which is greater: Sum of the integers from 1 to 40 inclusive
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04 Dec 2017, 22:09
04 Dec 2017, 22:09
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Bunuel wrote:
Quantity A |
Quantity B |
Sum of the integers from 1 to 40 inclusive |
800 |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Here to know the sum of n numbers both inclusive is given by = \(\frac{n(n+1)}{2}\)
So here n = 40
Therefore sum =\(\frac{(40 * 41)}{2}\) = 820.
Hence option A.
General Discussion
Sum of the integers from 1 to 40 inclusive
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23 Nov 2018, 03:59
23 Nov 2018, 03:59
Expert Reply
Quantity A |
Quantity B |
Sum of the integers from 1 to 40 inclusive |
800 |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
