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Which is greater: Sum of the integers from 1 to 40 inclusive
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Updated on: 30 Dec 2022, 08:37
Updated on: 30 Dec 2022, 08:37
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Question Stats:
26% (00:38) correct
73% (00:42) wrong based on 42 sessions
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Quantity A |
Quantity B |
Sum of the integers from 1 to 40 inclusive |
800 |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Re: Which is greater: Sum of the integers from 1 to 40 inclusive
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04 Dec 2017, 22:09
04 Dec 2017, 22:09
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Bunuel wrote:
Quantity A |
Quantity B |
Sum of the integers from 1 to 40 inclusive |
800 |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Kudos for correct solution.
Here to know the sum of n numbers both inclusive is given by = \(\frac{n(n+1)}{2}\)
So here n = 40
Therefore sum =\(\frac{(40 * 41)}{2}\) = 820.
Hence option A.
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Sum of the integers from 1 to 40 inclusive
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23 Nov 2018, 03:59
23 Nov 2018, 03:59
Expert Reply
Quantity A |
Quantity B |
Sum of the integers from 1 to 40 inclusive |
800 |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
_________________
Re: Sum of the integers from 1 to 40 inclusive
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23 Nov 2018, 10:15
23 Nov 2018, 10:15
1
Carcass wrote:
Quantity A |
Quantity B |
Sum of the integers from 1 to 40 inclusive |
800 |
A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
from the equation n(n+1)/2 = 40 * 41/2 = 41 * 20 > 40 * 20
Or since this is a consecutive integer form we can find the average as (last + first)/2
And the number of terms as (last - first) = 40 - 1 = 39 + 1 = 40
Answer choice A
Re: Which is greater: Sum of the integers from 1 to 40 inclusive
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17 Sep 2019, 02:08
17 Sep 2019, 02:08
QA = 820
Sum of the integers from 1 to 40
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21 Oct 2022, 04:17
21 Oct 2022, 04:17
Expert Reply
Quantity A |
Quantity B |
Sum of the integers from 1 to 40 |
800 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: Sum of the integers from 1 to 40
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21 Oct 2022, 12:23
21 Oct 2022, 12:23
1
(40+1)/2((40-1)+1) = 41/2(40) = 820
Quantity A is greater
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Quantity A is greater
Posted from my mobile device
Re: Sum of the integers from 1 to 40
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28 Oct 2022, 16:50
28 Oct 2022, 16:50
Quick question so I have the understanding:
sum of arithmetic sequence = (n/2)(a+L)
where n = number in the sequence, a = first number, L = last number
would n = 40?
sum of arithmetic sequence = (n/2)(a+L)
where n = number in the sequence, a = first number, L = last number
would n = 40?
Re: Sum of the integers from 1 to 40
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28 Oct 2022, 23:37
28 Oct 2022, 23:37
Expert Reply
\(1+2+3...........+n=\frac{n(n+1)}{2}\)
\(\frac{40(40+1)}{2}=20*41=820\)
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\(\frac{40(40+1)}{2}=20*41=820\)
_________________
gmatclubot
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