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x>y>0
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25 Jan 2020, 06:56
25 Jan 2020, 06:56
Expert Reply
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Question Stats:
76% (00:40) correct
23% (00:53) wrong based on 52 sessions
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\(x>y>0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
4x |
5y |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
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Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
x>y>0
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25 Jan 2020, 11:14
25 Jan 2020, 11:14
1
Carcass wrote:
\(x>y>0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
4x |
5y |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Let's test some possible values of x and y
case i: Since \(x>y>0\), one possible pair of values is \(x=5\) and \(y=4\)
We get:
Quantity A: \(4x = 4(5) = 20\)
Quantity B: \(5y = 5(4) = 20\)
In this case, the quantities are equal
case ii: Since \(x>y>0\), another possible pair of values is \(x=10\) and \(y=1\)
We get:
Quantity A: \(4x = 4(10) = 40\)
Quantity B: \(5y = 5(1) = 4\)
In this case, Quantity A is greater
Answer: D
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Re: x>y>0
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29 Jan 2020, 06:49
29 Jan 2020, 06:49
Put x =1/4 and y = 1/5 [satisfying x>y ]
Implies 1/4>1/5
4*x = 5*y
Put x=1, y= 2 [satisfying x>y ]
4*x = 4
5*y = 10
Clearly 'D'
Implies 1/4>1/5
4*x = 5*y
Put x=1, y= 2 [satisfying x>y ]
4*x = 4
5*y = 10
Clearly 'D'
