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Five sixth-grade classes are competing against one another i
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03 Aug 2020, 11:17
03 Aug 2020, 11:17
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Question Stats:
62% (01:18) correct
37% (01:09) wrong based on 160 sessions
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Five sixth-grade classes are competing against one another in an effort to raise money for a local charity. No class raised less than $ 60, and one class raised at least five times as much money as all the other classes combined.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The minimum average (arithmetic mean) amount raised by the five classes |
$240 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: Five sixth-grade classes are competing against one another i
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03 Aug 2020, 11:17
03 Aug 2020, 11:17
Expert Reply
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Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Re: Five sixth-grade classes are competing against one another i
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04 Aug 2020, 05:23
04 Aug 2020, 05:23
2
Minimum mean can be calculated when you have all 5 classes raising the least money.
minimum any class raised is 60 and one class raised 5 times the combined amount collected by other 4 class.
so, 4 * 60 + 5*4*60 = 1440
Average : 1440/5 = 288
Answer: A
minimum any class raised is 60 and one class raised 5 times the combined amount collected by other 4 class.
so, 4 * 60 + 5*4*60 = 1440
Average : 1440/5 = 288
Answer: A
