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a et b = a^2-ab
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02 Jan 2021, 10:43
02 Jan 2021, 10:43
Expert Reply
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Question Stats:
96% (00:19) correct
3% (00:12) wrong based on 28 sessions
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\(a \Cup b = a^2-ab\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(4 \Cup 3\) |
\(3 \Cup 4\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: a et b = a^2-ab
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03 Jan 2021, 03:08
03 Jan 2021, 03:08
1
Carcass wrote:
\(a \Cup b = a^2-ab\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(4 \Cup 3\) |
\(3 \Cup 4\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Given condition is: a⋓b = a^2 − ab.
Qty A: 4⋓3 = 4^2 - 4x3 --> 16 - 12 => 4.
Qty B: 3⋓4 = 3^2 - 3x4 --> 9 - 12 => -3.
Hence Qty A is greater.
gmatclubot
Re: a et b = a^2-ab [#permalink]
03 Jan 2021, 03:08
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