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Team A has a 50% chance of winning any game that it plays. Team B has
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18 Mar 2021, 02:40
18 Mar 2021, 02:40
Expert Reply
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Question Stats:
70% (01:11) correct
29% (00:51) wrong based on 44 sessions
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Team A has a 50% chance of winning any game that it plays. Team B has a 60% chance of winning any game that it plays.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Quantity A |
Quantity B |
The probability that Team A will win its next three games in a row |
The probability that Team B will win its next four games in a row |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Team A has a 50% chance of winning any game that it plays. Team B has
[#permalink]
18 Mar 2021, 06:53
18 Mar 2021, 06:53
1
Carcass wrote:
Team A has a 50% chance of winning any game that it plays. Team B has a 60% chance of winning any game that it plays.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The probability that Team A will win its next three games in a row |
The probability that Team B will win its next four games in a row |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
\(P(A) = 0.5\)
\(P(B) = 0.6\)
Col. A: \((0.5)(0.5)(0.5) = \frac{125}{1000}\)
Col. B : \((0.6)(0.6)(0.6)(0.6) = \frac{1296}{10000}\)
Cross-multiply the denominators:
Col. A: \(1250\)
Col. B : \(1296\)
Hence, option B
Team A has a 50% chance of winning any game that it plays. Team B has
[#permalink]
18 Mar 2021, 11:01
18 Mar 2021, 11:01
I found it easier to solve by converting everything to fraction form.
QA: (1/2)(1/2)(1/2) = 1/8
QB: (3/5)(3/5)(3/5)(3/5) = 81/625, or approximately .129
.129 > .125 (the decimal form of 1/8), so QB is greater.
QA: (1/2)(1/2)(1/2) = 1/8
QB: (3/5)(3/5)(3/5)(3/5) = 81/625, or approximately .129
.129 > .125 (the decimal form of 1/8), so QB is greater.
