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It is given that [#permalink]
1
Expert Reply
\((x-5)(x+6)=0\)

\(x-5=0\) and \(x+6=0\)

Now,

\(x=5\) and \(x=-6\)

If you substitute in quantity A the two values of x A is always <0

\(+5-6=-1\)

\(-6-6=-12
\)

In both cases, 0 is greater

B i the answer

Hope this helps
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Re: It is given that [#permalink]
1
Carcass wrote:
(x-5)(x+6)=0

x-5=0 and x+6=0

Now,

x=5 and x=-6

If you substitute in quantity A the two values of x A is always <0

+5-6=-1

-6-6=-12

In both cases, 0 is greater

B i the answer

Hope this helps


Thank you!
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