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Points A, B, and C are three different points on a circle, which has a
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06 May 2021, 04:17
06 May 2021, 04:17
Expert Reply
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Question Stats:
45% (01:34) correct
54% (01:27) wrong based on 48 sessions
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Points A, B, and C are three different points on a circle, which has area equal to \(64\pi.\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Quantity A |
Quantity B |
AB+AC |
32 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Points A, B, and C are three different points on a circle, which has a
[#permalink]
06 May 2021, 08:36
06 May 2021, 08:36
2
Solution:
Area of the circle=π\(r^2\).
64π=π\(r^2\)
r=8
Thus, if AB/AC is on the diameter it can be 16.
But both of them cannot be on the diameter and one of them has to be less than 16.
Making the sum of the two less than 32
Qty A< Qty B
IMO B
Hope this helps!
Area of the circle=π\(r^2\).
64π=π\(r^2\)
r=8
Thus, if AB/AC is on the diameter it can be 16.
But both of them cannot be on the diameter and one of them has to be less than 16.
Making the sum of the two less than 32
Qty A< Qty B
IMO B
Hope this helps!
Re: Points A, B, and C are three different points on a circle, which has a
[#permalink]
06 May 2021, 20:35
06 May 2021, 20:35
Ks1859 wrote:
Solution:
Area of the circle=π\(r^2\).
64π=π\(r^2\)
r=8
Thus, if AB/AC is on the diameter it can be 16.
But both of them cannot be on the diameter and one of them has to be less than 16.
Making the sum of the two less than 32
Qty A< Qty B
IMO B
Hope this helps!
Area of the circle=π\(r^2\).
64π=π\(r^2\)
r=8
Thus, if AB/AC is on the diameter it can be 16.
But both of them cannot be on the diameter and one of them has to be less than 16.
Making the sum of the two less than 32
Qty A< Qty B
IMO B
Hope this helps!
i understand your reasoning but, the info only said 3 point of circle and nothing else
from that we can consider there may two diameter or two chords or one diameter and one chord....shouldn't ans be option D not sufficient into to reach one result
