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A farmer purchased several animals from a neighboring farmer: 6 animal
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13 May 2021, 10:05
13 May 2021, 10:05
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A farmer purchased several animals from a neighboring farmer: 6 animals costing $50 each, 10 animals costing $100 each, and 𝑘 animals costing $200 each, where 𝑘 is a positive odd integer. The median price for all the animals was $100.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Quantity A |
Quantity B |
k |
16 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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A farmer purchased several animals from a neighboring farmer: 6 animal
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13 May 2021, 23:51
13 May 2021, 23:51
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Carcass wrote:
A farmer purchased several animals from a neighboring farmer: 6 animals costing $50 each, 10 animals costing $100 each, and 𝑘 animals costing $200 each, where 𝑘 is a positive odd integer. The median price for all the animals was $100.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
k |
16 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Since K is an odd integer, the total number of terms (n) would be odd = 16 + K = even + odd = odd
So, Median would be the \(\frac{(n+1)}{2}^{th}\) term
Let's maximize the value of K;
| 1 2 3 4 5 6 | 7 8 9 10 11 12 13 14 15 16 | K
In order to have maximum number of terms, we will take the \(16^{th}\) term as the median
This means we will have 15 terms to it's left and 15 to the right
Therefore, k(max.) = 15
Col. A: 15
Col. B: 16
Hence, option B
Re: A farmer purchased several animals from a neighboring farmer: 6 animal
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04 Mar 2023, 05:21
04 Mar 2023, 05:21
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