Carcass wrote:
A farmer purchased several animals from a neighboring farmer: 6 animals costing $50 each, 10 animals costing $100 each, and š animals costing $200 each, where š is a positive odd integer. The median price for all the animals was $100.
Quantity A |
Quantity B |
k |
16 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Since K is an odd integer, the total number of terms (n) would be odd = 16 + K = even + odd = odd
So, Median would be the
(n+1)2th term
Let's maximize the value of K;
| 1 2 3 4 5 6 | 7 8 9 10 11 12 13 14 15 16 | K
In order to have maximum number of terms, we will take the
16th term as the median
This means we will have 15 terms to it's left and 15 to the right
Therefore, k(max.) = 15
Col. A: 15
Col. B: 16
Hence, option B