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n is an integer, and k is not an integer. 0 < k < n < k + 2.
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06 Nov 2019, 09:16
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n is an integer, and k is not an integer.
\(0 < k < n < k + 2.\)
Quantity A
Quantity B
n
k+1
A. Quantity A is greater. B. Quantity B is greater. C. The two quantities are equal. D. The relationship cannot be determined from the information given.
n is an integer, and k is not an integer. 0 < k < n < k + 2.
[#permalink]
06 Nov 2019, 09:27
1
Carcass wrote:
n is an integer, and k is not an integer.
\(0 < k < n < k + 2\)
Quantity A
Quantity B
n
k+1
A. Quantity A is greater. B. Quantity B is greater. C. The two quantities are equal. D. The relationship cannot be determined from the information given.
First notice that \(0 < k < k+1 < k+2\) However, when we try to add the n to this inequality, we can't tell where it goes. It COULD be the case that we have: \(0 < k < n < k+1 < k+2\) OR It COULD be the case that we have: \(0 < k < k+1 < n < k+2\)
This certainly suggests that the correct answer is D. However, let's be sure and find some possible values to test.
case i: Since n is an integer, and k is not an integer and since \(0 < k < n < k + 2\), one possible pair of values is \(n=3\) and \(k=1.5\) We get: Quantity A: n = 3 Quantity B: k + 1 = 1.5 + 1 = 2.5 In this case, Quantity A is greater
case ii: Another possible pair of values is \(n=2\) and \(k=1.5\) We get: Quantity A: n = 2 Quantity B: k + 1 = 1.5 + 1 = 2.5 In this case, Quantity B is greater
Re: n is an integer, and k is not an integer. 0 < k < n < k + 2.
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18 Jun 2021, 11:37
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Re: n is an integer, and k is not an integer. 0 < k < n < k + 2. [#permalink]