95 is out, and only 9 integers are left between 91 and 100
let's count the possible test lowest results observing if their average is integer always: 91, 93, 92, 96, 98, 94
the average of the six above series would result in 90*6+(1+3+2+6+8+4) divided by 6, which is 90+4,
BUT tricky part is that after 95 as the 7th test result the average is not an integer.
Therefore, series is modified to contain 91, 93, 92, 96, 98, 100 and 95. Hence, 6th term can be only
100.
Answer is
AIMO it's very hard level question asking solution under GRE time constraint
![Sad :(](/forum/images/smilies/1f61f.png)
KarunMendiratta wrote:
A person took a total of 7 tests and received 7 different scores, each an integer between 91 and 100, inclusive.
After each test the average of his test scores was an integer and his score on the \(7^{th}\) test was 95.
Quantity A |
Quantity B |
Score on the \(6^{th}\) test |
96 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given