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x> 0
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Updated on: 09 Feb 2022, 12:09
Updated on: 09 Feb 2022, 12:09
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Question Stats:
82% (01:01) correct
17% (01:11) wrong based on 17 sessions
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\(x> 0\)
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{1}{x }\) |
\(\frac{(x-1)}{x^2}\) |
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
Originally posted by schrodinger on 09 Feb 2022, 10:51.
Last edited by Carcass on 09 Feb 2022, 12:09, edited 1 time in total.
Last edited by Carcass on 09 Feb 2022, 12:09, edited 1 time in total.
Formatted
Re: x> 0
[#permalink]
09 Feb 2022, 12:13
09 Feb 2022, 12:13
2
Expert Reply
Just picking numbers and you solve in 30 seconds
or using the fraction properties
\(A >>> \frac{1}{x}\)
B is \(\frac{x}{x^2}-\frac{1}{x^2}\)
\(\frac{1}{x}-\frac{1}{x^2}\)
so A is just \(\frac{1}{x}\) and B is \(\frac{1}{x} \) minus something else more
A must be bigger
or using the fraction properties
\(A >>> \frac{1}{x}\)
B is \(\frac{x}{x^2}-\frac{1}{x^2}\)
\(\frac{1}{x}-\frac{1}{x^2}\)
so A is just \(\frac{1}{x}\) and B is \(\frac{1}{x} \) minus something else more
A must be bigger
gmatclubot
Re: x> 0 [#permalink]
09 Feb 2022, 12:13
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