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schrodinger
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x> 0 [#permalink] New post   Updated on: 09 Feb 2022, 12:09
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\(x> 0\)

Quantity A
Quantity B
\(\frac{1}{x }\)
\(\frac{(x-1)}{x^2}\)



A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
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A

Originally posted by schrodinger on 09 Feb 2022, 10:51.
Last edited by Carcass on 09 Feb 2022, 12:09, edited 1 time in total.
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Re: x> 0 [#permalink] New post   09 Feb 2022, 12:13
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Just picking numbers and you solve in 30 seconds

or using the fraction properties

\(A >>> \frac{1}{x}\)

B is \(\frac{x}{x^2}-\frac{1}{x^2}\)

\(\frac{1}{x}-\frac{1}{x^2}\)

so A is just \(\frac{1}{x}\) and B is \(\frac{1}{x} \) minus something else more

A must be bigger
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Re: x> 0 [#permalink]
09 Feb 2022, 12:13
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