GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 28Live Online Class with Top GRE Expert Mike Butville
08:00 PM EDT
-10:00 PM EDT
Top scores are possible when you enroll in a powerful GRE course, taught live online + 6 months access to TTP GRE OnDemand video courses included! Class starts Mon/Wed Sept. 28, 2026 - Dec. 9, 2026, 8:00pm-10:00pm EST
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Height [m]h[/m] (in meters) of a ball thrown upwards is given by equat
[#permalink]
06 Mar 2021, 05:11
06 Mar 2021, 05:11
00:00
Question Stats:
70% (01:56) correct
29% (01:39) wrong based on 24 sessions
Hide Show timer Statistics
Height \(h\) (in meters) of a ball thrown upwards is given by equation \(h = -3(t - 6)^2 + 108\)
(A) Quantity A is greater
(B) Quantity B is greater
(C) The two quantities are equal
(D) The relationship cannot be determined from the information given
Quantity A |
Quantity B |
Height of ball 3.5 seconds after it was launched |
Height of ball 2 seconds after it reaches maximum height |
(A) Quantity A is greater
(B) Quantity B is greater
(C) The two quantities are equal
(D) The relationship cannot be determined from the information given
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: Height [m]h[/m] (in meters) of a ball thrown upwards is given by equat
[#permalink]
06 Mar 2021, 23:31
06 Mar 2021, 23:31
2
OA Explanation
\(h = -3(t - 6)^2 + 108\)
x-coordinates of the vertex of parabola is \(6\)
y-coordinate of the vertex of parabola (Max. point) is \(108\)
Col. A: Value of \(y\) when \(x = 3.5\)
Col. B: Value of \(y\) when \(x = (6 + 2) = 8\)
Col. A: \(89.25\)
Col. B: \(96\)
Hence, option B
\(h = -3(t - 6)^2 + 108\)
x-coordinates of the vertex of parabola is \(6\)
y-coordinate of the vertex of parabola (Max. point) is \(108\)
Col. A: Value of \(y\) when \(x = 3.5\)
Col. B: Value of \(y\) when \(x = (6 + 2) = 8\)
Col. A: \(89.25\)
Col. B: \(96\)
Hence, option B
Re: Height [m]h[/m] (in meters) of a ball thrown upwards is given by equat
[#permalink]
11 Mar 2021, 02:43
11 Mar 2021, 02:43
x value is substitute at t,right?
for QB,
h=-3(2-6)^2+108= -3*(-4)^2+108=-3*16+108=60....
how your QB h=96?
for QB,
h=-3(2-6)^2+108= -3*(-4)^2+108=-3*16+108=60....
how your QB h=96?
