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GRE Math Challenge #25- The arithmetic mean of w,x and y is
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Updated on: 17 Feb 2020, 11:12
Updated on: 17 Feb 2020, 11:12
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Question Stats:
63% (01:03) correct
36% (01:00) wrong based on 215 sessions
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The arithmetic mean of w,x and y is 9
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The average of 2w-y, 3x+6 and 3y-x |
20 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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Re: GRE Math Challenge #25
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18 May 2015, 17:07
18 May 2015, 17:07
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sandy wrote:
The arithmetic mean of w,x and y is 9
Column A: The average of 2w-y, 3x+6 and 3y-x
Column B: 20
Column A: The average of 2w-y, 3x+6 and 3y-x
Column B: 20
Given: The arithmetic mean of w, x and y is 9
This means that (w + x + y)/3 = 9
Multiply both sides of the equation by 3 to get: w + x + y = 27
Column A: The average of 2w-y, 3x+6 and 3y-x
Average of these 3 values = [(2w-y) + (3x+6) + (3y-x)]/3
Simplify numerator to get: [2w + 2x + 2y + 6]/3
Factor the numerator to get: [2(w + x + y + 3]/3
KEY STEP: Replace w + x + y with 27 [from earlier conclusion with given information]
We get: [2(27 + 3]/3
Simplify: 60/3 = 20
Column B: 20
Answer:
Show: ::
C
Cheers,
Brent
Re: GRE Math Challenge #25- The arithmetic mean of w,x and y is
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17 Feb 2020, 11:13
17 Feb 2020, 11:13
Expert Reply
Bump for further discussion.
Regards
Regards
