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a<0
[#permalink]
31 May 2022, 01:00
31 May 2022, 01:00
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Question Stats:
81% (00:22) correct
18% (01:03) wrong based on 16 sessions
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\(a<0\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(2a^2\) |
\(a^3\) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
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GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
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Re: a<0
[#permalink]
31 May 2022, 07:19
31 May 2022, 07:19
1
Carcass wrote:
\(a<0\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(2a^2\) |
\(a^3\) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
We can quickly solve this question using matching operations (see the video lesson below )
Given:
Quantity A: 2a²
Quantity B: a³
Since we can be certain that a² is positive, we can safely divide both quantities by a² to get:
Quantity A: 2
Quantity B: a
Since we're told a is negative, it's clear that Quantity A is greater.
Answer: A
RELATED VIDEO
Re: a<0
[#permalink]
05 Jun 2022, 07:19
05 Jun 2022, 07:19
1
Solve instantly by noting that a negative squared always becomes positive, while a negative cubed always remains negative. Thus, A must be greater.
