GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the figure, P and Q are centers of the two circles of rad
[#permalink]
24 Mar 2019, 00:27
24 Mar 2019, 00:27
1
Expert Reply
4
Bookmarks
00:00
Question Stats:
39% (01:27) correct
60% (01:31) wrong based on 91 sessions
Hide Show timer Statistics
Attachment:
#GREpracticequestion In the figure, P and Q are centers .jpg [ 28.93 KiB | Viewed 9163 times ]
In the figure, P and Q are centers of the two circles of radii 3 and 4, respectively. A and B are the points at which a common tangent touches each circle.
Quantity A |
Quantity B |
\(AB\) |
\(PQ\) |
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Re: In the figure, P and Q are centers of the two circles of rad
[#permalink]
27 Mar 2019, 14:16
27 Mar 2019, 14:16
7
Expert Reply
3
Bookmarks
Tough one
shot7.jpg [ 32.12 KiB | Viewed 8740 times ]
\(ABPD\) is a rectangle and \(AB=DP\). A is \(\angle90°\) so also the corresponding angle D must be \(90°\). If D is \(90° PQ\) is the longest side of the \(\trinagle PDQ\).
Sp \(PQ\) is > of side \(DP\). \(DP\) is \(= AB\).
Therefore, \(PQ > AB\)
B is the answer
Attachment:
shot7.jpg [ 32.12 KiB | Viewed 8740 times ]
\(ABPD\) is a rectangle and \(AB=DP\). A is \(\angle90°\) so also the corresponding angle D must be \(90°\). If D is \(90° PQ\) is the longest side of the \(\trinagle PDQ\).
Sp \(PQ\) is > of side \(DP\). \(DP\) is \(= AB\).
Therefore, \(PQ > AB\)
B is the answer
General Discussion
Re: In the figure, P and Q are centers of the two circles of rad
[#permalink]
27 Mar 2019, 08:57
27 Mar 2019, 08:57
1
please provide explanation for the answer?
