Re: a < b
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22 May 2023, 17:11
Given the inequality a < b, we can evaluate Quantities A and B.
Quantity A: |a + b|
Since a and b are on the number line and a < b, their sum (a + b) will also be positive. Hence, |a + b| equals (a + b).
Quantity B: |a - b|
Since a is less than b (a < b), their difference (a - b) is negative. When you take the absolute value of a negative number, you get a positive number. Hence, |a - b| equals (b - a).
So, we now compare (a + b) and (b - a).
Because a < b, we can infer that a + b < b + b, or a + b < 2b.
But from |a - b|, we have b - a. This would be less than 2b - a, which we just found to be less than a + b. Therefore, b - a < a + b.
Hence, Quantity B (b - a) is less than Quantity A (a + b).
So, Option A: Quantity A is greater, is the correct answer.