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ab<1 and ac<1
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19 Mar 2024, 09:48
19 Mar 2024, 09:48
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Question Stats:
42% (02:00) correct
57% (02:13) wrong based on 7 sessions
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\(ab<1 \)
\(ac<1\)
\(cb<1\)
\(abc=1\)
\(b>1\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\(ac<1\)
\(cb<1\)
\(abc=1\)
\(b>1\)
Quantity A |
Quantity B |
\(\dfrac{1}{a+c}\) |
\(b\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Re: ab<1 and ac<1
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10 Apr 2024, 00:01
10 Apr 2024, 00:01
1
Expert Reply
Dealin' with this problem is nasty.
Picking numbers could be cumbersome and at the same time you will have a lot of errors.
abc=1 and we do know that b is positive >1 and could be any number: integer or fraction
at the same time picking be you have to make consistent the inequalities above such as ac<1 and the others. mhhhhh too lengthy
working with the inequalities themselves, pairing all of them is lengthy as well
Maybe the best approach is using the positive and negative assessment
We do know that b is positive and at the same time abc=1 . To be ABC =1 and b positive, a and c must be balance b in order to have 1 in the end. a and c NOT necessarily must be negative but considering that the
ab<1
ac<1
cb<1
a and c must be negative
In quantity A 1/a+c we do have a negative fraction and b we do know is positive
A is negative
B is positive
B > A
The answer is B
Picking numbers could be cumbersome and at the same time you will have a lot of errors.
abc=1 and we do know that b is positive >1 and could be any number: integer or fraction
at the same time picking be you have to make consistent the inequalities above such as ac<1 and the others. mhhhhh too lengthy
working with the inequalities themselves, pairing all of them is lengthy as well
Maybe the best approach is using the positive and negative assessment
We do know that b is positive and at the same time abc=1 . To be ABC =1 and b positive, a and c must be balance b in order to have 1 in the end. a and c NOT necessarily must be negative but considering that the
ab<1
ac<1
cb<1
a and c must be negative
In quantity A 1/a+c we do have a negative fraction and b we do know is positive
A is negative
B is positive
B > A
The answer is B
