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Re: (3x – 4y)(3x + 4y) = 2 [#permalink]
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A: 9x² – 16y² = 2
B: 4

Answer is B
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Re: (3x – 4y)(3x + 4y) = 2 [#permalink]
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This question tests whether you know the "difference of squares" formula: a^2 - b^2 = (a+b)*(a-b)
No real traps in this question.
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Re: (3x 4y)(3x + 4y) = 2 [#permalink]
IMO if we look closely at Quant A, you'll notice it is equivalent to the given (3x-4y)(3x+4y) which is = 2. Thus QA = 2. Comparing QA to QB, QB is greater. Therefore B is answer.
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(3x 4y)(3x + 4y) = 2 [#permalink]
Expand \((3x-4y)(3x+4y)\) to get \(9x^2 + 12y -12y -16y^2 = 9x^2 - 16y^2\)

Since \((3x-4y)(3x+4y)=2, \text{ } \,\,\,\,\,\, 9x^2 - 16y^2=2\)

Quantity A: \(9x^2 - 16y^2 = 2\)
Quantity B: \(4\)

Therefore, Quantity B is always greater.
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