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x > y xy 0
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20 May 2018, 16:56
20 May 2018, 16:56
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\(x > y\)
\(xy \neq 0\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
\(xy \neq 0\)
Quantity A |
Quantity B |
\(\frac{x^2}{y+\frac{1}{y}}\) |
\(\frac{y^2}{x+\frac{1}{x}}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: x > y xy 0
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20 May 2018, 22:57
20 May 2018, 22:57
We can spend a lot of time looking for an algebraic solution. However, the best strategy is to just plug in numbers.
Given: x>y
1) x = 3 and y = 2 gives quantity A greater than quantity B
2) x = 3 and y = -2 gives quantity B greater than quantity A
Hence, D
Given: x>y
1) x = 3 and y = 2 gives quantity A greater than quantity B
2) x = 3 and y = -2 gives quantity B greater than quantity A
Hence, D
Re: x > y xy 0
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20 Sep 2025, 22:42
20 Sep 2025, 22:42
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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