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x > y xy 0

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sandy
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x > y xy 0 [#permalink] New post   20 May 2018, 16:56
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\(x > y\)
\(xy \neq 0\)

Quantity A
Quantity B
\(\frac{x^2}{y+\frac{1}{y}}\)
\(\frac{y^2}{x+\frac{1}{x}}\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
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D
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novice07
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Re: x > y xy 0 [#permalink] New post   20 May 2018, 22:57
We can spend a lot of time looking for an algebraic solution. However, the best strategy is to just plug in numbers.

Given: x>y
1) x = 3 and y = 2 gives quantity A greater than quantity B

2) x = 3 and y = -2 gives quantity B greater than quantity A

Hence, D
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gmatclubot
Re: x > y xy 0 [#permalink]
20 May 2018, 22:57
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