Carcass wrote:
Of the 312 employees of Company X, \(\frac{1}{3}\) are in division A and the rest are in division B. Women account for \(\frac{2}{3}\) pf all employees. If \(\frac{5}{8 }\) of the women are in division B, how many men are in division A ?
A. 26
B. 35
C. 78
D. 104
E. 130
Kudos for the right answer and explanation
Here,
\(\frac{1}{3}\) are in division A = \(\frac{1}{3} * 312\) = \(104\)
Employees remaining in Div B = \(312 - 104 = 208\)
Total women employees = \(\frac{2}{3} * 312\) = 208No. of women employees in Div B = \(\frac{5}{8 } * 208\) = 130
Women employees in Div A = \(208 - 130 = 78\)
and
no. of men employees in Div A =\( 104 - 78 = 26\)