k and m are different integers

Currently, k=m, because both k and m equal to 12

\(12 \sqrt{12} = k \sqrt{m}\)

The variable m is the value under the square root symbol, rather than the value that results when m is placed under the square root symbol.

So if k and m are currently equal, but k must be different than m, how can we increase k or m ?? Factoring the square root

\(12 \times \sqrt{12} \)

\(12 \times \sqrt{4} \times \sqrt{3}\)

\(12 \times \pm 2 \times \sqrt{3}\)

\(24 \times \sqrt{3}\) or \(-24 \times \sqrt{3}\)

Now \(k = 24\) or \(k = -24\) and \(m=3\). Find \(k+m\): \(24+3=27\) or \(-24+3=-21\)

B and E are the answers